Carbon and Its Compounds – Case-based Questions with Answers
Chemistry — Chapter 4: Carbon and Its Compounds
CBSE Class 10 Science — Chapter Wise Study Materials Based on NCERT
15 Case-Based Questions with model answers — excellent for higher-order thinking and board exam preparation.
Case 1 — The Household Cleaner
Riya notices that her regular soap leaves a white scummy deposit on her utensils when washing in the tap water at home. She reads that detergents are used to avoid this problem.
Questions:
- Explain why soap forms scum in hard water.
- Mention two reasons detergents are preferred in hard water.
Answers:
- Why scum forms: Soap anions (RCOO⁻) react with Ca²⁺/Mg²⁺ ions in hard water to form insoluble calcium or magnesium salts (scum) which precipitate out and reduce cleaning efficiency.
- Why detergents preferred:
- Detergents contain sulphonate or sulfate groups that remain soluble in hard water and do not form insoluble precipitates with Ca²⁺/Mg²⁺.
- They can be formulated for specific cleaning tasks and work effectively at lower concentrations and in colder water.
Case 2 — The Fruit Aroma
A small food‑processing unit uses a fruity fragrance in jam and wants to prepare a compound with a pleasant smell similar to ester compounds found in fruits.
Questions:
- Suggest a simple ester that gives a fruity smell and write its formation equation.
- State the catalyst used and explain why esters have fruity odours.
Answers:
- Suggested ester: Ethyl ethanoate (ethyl acetate) — commonly smells like pears or fruity notes.
- Formation equation: CH₃CH₂OH + CH₃COOH ⇌ CH₃COOCH₂CH₃ + H₂O (conc. H₂SO₄ catalyst).
- Catalyst and reason for smell: Concentrated sulfuric acid is used as catalyst and dehydrating agent; esters are often volatile with molecular structures that interact with olfactory receptors producing pleasant fruity odours.
Case 3 — The Burning Stove
During cooking with a gas stove, incomplete combustion sometimes produces a faint smell and soot deposits. A student is asked to explain the chemistry.
Questions:
- What are the products of complete and incomplete combustion of carbon compounds?
- Why is incomplete combustion hazardous?
Answers:
- Products:
- Complete combustion — CO₂ and H₂O (e.g., CH₄ + 2O₂ → CO₂ + 2H₂O).
- Incomplete combustion — CO, C (soot) and partially oxidised hydrocarbons.
- Hazard: Carbon monoxide (CO) is toxic (binds haemoglobin), soot causes respiratory issues and incomplete combustion indicates inefficient fuel use; ensure adequate oxygen supply and ventilation to prevent hazards.
Case 4 — The Lab Oxidation
A student oxidises ethanol carefully to obtain ethanal but accidentally continues heating and obtains ethanoic acid.
Questions:
- Write the two-step oxidation sequence with reagents.
- How can the student stop at ethanal rather than proceed to ethanoic acid?
Answers:
- Oxidation sequence:
- CH₃CH₂OH (ethanol) —[O]→ CH₃CHO (ethanal) —[O]→ CH₃COOH (ethanoic acid).
- Common reagents: Acidified K₂Cr₂O₇ or KMnO₄.
- Stop at ethanal: Use controlled, mild oxidation conditions and remove aldehyde as it forms (distillation) to prevent further oxidation to acid; use milder oxidants and lower temperatures.
Case 5 — The Soap Maker
An artisan wants to make soap from animal fat using traditional methods and asks for the chemical process explanation.
Questions:
- Explain the saponification reaction with a simple equation.
- State the two main products and their roles.
Answers:
- Saponification equation: Triglyceride (fat) + 3 NaOH → Glycerol + 3 RCOONa (soap).
- Products and roles:
- Glycerol — a byproduct used in cosmetics and as a humectant.
- Sodium salts of fatty acids (soap) — act as surfactants to emulsify oils/dirt enabling removal with water.
Case 6 — The Distillation Setup
During an experiment to prepare ethyl ethanoate, students set up a distillation to separate product. They need to rationalise conditions used.
Questions:
- Why is heating under reflux often used before distillation for esterification?
- How does removal of water affect equilibrium?
Answers:
- Reflux purpose: Ensures reactants react at elevated temperature while preventing loss of volatile compounds; allows reaction to reach equilibrium.
- Removal of water: According to Le Chatelier's principle, removing water (a product) shifts equilibrium towards ester formation, increasing yield; distillation helps separate and collect the ester once formed.
Case 7 — The Smelly Accident
In a kitchen chemistry demonstration, a student spills a small amount of ethanoic acid. The pungent smell is noticeable. Peers ask why the acid has a strong smell compared to ethanol.
Questions:
- Explain why ethanoic acid has a stronger (pungent) odour than ethanol.
- List safety steps to take for a spill of a weak carboxylic acid.
Answers:
- Odour reason: Ethanoic acid is volatile and has a polar —COOH group that interacts strongly with olfactory receptors; its acidic nature adds to the sharp vinegar‑like smell compared to the milder smell of ethanol.
- Safety steps:
- Ventilate the area and avoid inhaling vapours.
- Wear gloves and clean with water and baking soda (mild base) to neutralise small spills; dispose of waste per lab guidelines.
Case 8 — The Structural Puzzle
Two compounds have the molecular formula C₄H₈. A student is asked to identify possible types of isomerism and name two structural isomers.
Questions:
- What kinds of isomerism could C₄H₈ exhibit?
- Name two structural isomers of C₄H₈.
Answers:
- Types of isomerism: Structural (chain and position) isomerism and because C₄H₈ is unsaturated, it can exhibit cis‑trans (geometric) isomerism if it contains a C=C with different substituents.
- Two structural isomers: 1‑butene (CH₂=CH–CH₂–CH₃) and 2‑butene (CH₃–CH=CH–CH₃) — 2‑butene also has cis/trans isomers.
Case 9 — The Oxidation Observation
In a test, an aldehyde gives a silver mirror with Tollens' reagent, but a ketone does not. A group discussion explores why.
Questions:
- Explain the chemical reason for the positive Tollens' test with aldehydes.
- Why do ketones generally not give a Tollens' test?
Answers:
- Aldehyde reaction: Aldehydes are easily oxidised to carboxylic acids; they reduce Ag⁺ in Tollens' reagent to metallic silver, forming a silver mirror.
- Ketone behaviour: Ketones are less susceptible to oxidation under mild conditions and therefore do not reduce Ag⁺; they usually give a negative Tollens' test.
Case 10 — The Solubility Query
A student compares solubility of ethanol, propanol and butanol in water and notes decreasing solubility with longer chain length.
Questions:
- Explain why solubility in water decreases as alkyl chain length increases.
- Mention which of these is most soluble and why.
Answers:
- Reason: While the —OH group can hydrogen bond with water, the non‑polar hydrocarbon chain is hydrophobic; as chain length increases, hydrophobic character dominates and reduces solubility.
- Most soluble: Ethanol is most soluble (completely miscible) because its short chain makes the polar —OH group's effect dominant.
Case 11 — The Reaction Rate
During an esterification, two students test reaction rates using different catalysts and temperatures.
Questions:
- How do concentration, temperature and catalyst affect the rate and equilibrium of esterification?
- Suggest a practical way to increase ester yield in the lab.
Answers:
- Effects:
- Increasing concentration of reactants increases collision frequency and rate.
- Raising temperature speeds up rate but may affect equilibrium (often faster forward and reverse rates).
- Catalyst (H₂SO₄) increases rate by providing an alternate pathway without being consumed.
- Practical yield increase: Use excess alcohol or remove water as formed (e.g., using a drying agent or azeotropic distillation) to shift equilibrium toward ester products.
Case 12 — The Naming Challenge
Students are given CH₃–CH(OH)–CH₃ and asked to provide the IUPAC name and identify functional group and whether it is primary, secondary or tertiary.
Questions:
- Give the IUPAC name of CH₃–CH(OH)–CH₃.
- Identify the functional group and classify it as primary/secondary/tertiary.
Answers:
- IUPAC name: Propan‑2‑ol (commonly isopropanol).
- Functional group: —OH (alcohol); the carbon bearing —OH is attached to two other carbons, so it is a secondary alcohol.
Case 13 — The Eco-Friendly Soap
A company wants to market a biodegradable soap made from vegetable oils and asks how biodegradability and cleaning effectiveness relate to molecular structure.
Questions:
- Explain why soaps from natural fats are biodegradable.
- How does chain length of fatty acids affect soap properties?
Answers:
- Biodegradability: Natural fats are triglycerides of fatty acids which microorganisms can metabolise, breaking down soap molecules into CO₂, water and biomass; biodegradable soaps often have simpler structures amenable to microbial enzymes.
- Chain length effects:
- Shorter chains yield soaps that are more soluble and produce more lather but may be harsher.
- Longer chains improve cleansing of oily dirt (stronger hydrophobic interaction) but may be less soluble and harder (solid soap).
Case 14 — The Industrial Cleaner
An industrial plant needs to select a cleaning agent that is effective in hard, mineral-rich water and low temperatures.
Questions:
- Recommend whether soap or detergent is more suitable and justify.
- Mention one environmental consideration when choosing detergents.
Answers:
- Recommendation: Detergent is more suitable because it remains effective in hard water and at lower temperatures; its surfactant head groups do not precipitate with Ca²⁺/Mg²⁺.
- Environmental consideration: Some synthetic detergents are not readily biodegradable and can cause eutrophication or persistent pollution; choose biodegradable formulations and proper waste treatment.
Case 15 — The Exam Revision
A student prepares for board exams and needs a concise checklist to remember reactions and key facts from this chapter.
Questions:
- Provide a 6‑point checklist covering definitions, reactions and safety tips relevant for exams.
Answer — 6‑point checklist:
- Understand tetravalency and catenation as reasons for carbon’s diversity.
- Remember general formulas and examples for alkanes, alkenes; know isomerism basics.
- Know functional groups —OH, —COOH, —COOR and typical reactions (oxidation, esterification, saponification).
- Practice writing balanced equations for combustion, esterification and saponification.
- Recall physical property trends: solubility, boiling point influences (H‑bonding, chain length, branching).
- Safety: handle oxidising agents and strong acids/bases with care; ensure ventilation for combustion experiments; neutralise spills appropriately.
