Class 10 Maths Word Problems MCQs on Trigonometry Applications
Class 10 Maths Word Problems MCQs on Trigonometry Applications
Class: 10 | Subject: Mathematics
Chapter 9: Some Applications of Trigonometry
Board: CBSE Board Examination (Based on Latest NCERT Curriculum)
1. A tower casts a shadow of 30 m when the angle of elevation of the sun is 45°. Find the height of the tower.
Correct Answer: B. 30 m
Explanation: tan 45° = height/shadow = h/30. Since tan 45° = 1, h = 30 m.
Explanation: tan 45° = height/shadow = h/30. Since tan 45° = 1, h = 30 m.
2. From a point 40 m away from the base of a building, the angle of elevation is 30°. Find the height of the building.
Correct Answer: A. 40/√3 m
Explanation: tan 30° = h/40. Since tan 30° = 1/√3, h = 40/√3 m.
Explanation: tan 30° = h/40. Since tan 30° = 1/√3, h = 40/√3 m.
3. The angle of depression of a car from a cliff 50 m high is 45°. Find the distance of the car from the base of the cliff.
Correct Answer: B. 50 m
Explanation: tan 45° = height/base = 50/d ⇒ d = 50 m.
Explanation: tan 45° = height/base = 50/d ⇒ d = 50 m.
4. A flagstaff 12 m high casts a shadow 4√3 m long. Find the angle of elevation.
Correct Answer: C. 60°
Explanation: tan θ = 12/(4√3) = 12/ (4√3)= 3/√3= √3 ⇒ θ=60°.
Explanation: tan θ = 12/(4√3) = 12/ (4√3)= 3/√3= √3 ⇒ θ=60°.
5. A kite is flying at a height of 60 m. The string makes an angle of 30° with the ground. Find the length of the string.
Correct Answer: B. 120 m
Explanation: sin30° = height/hypotenuse = 60/L ⇒ 1/2=60/L ⇒ L=120 m.
Explanation: sin30° = height/hypotenuse = 60/L ⇒ 1/2=60/L ⇒ L=120 m.
6. From a ship, the angle of elevation of the top of a lighthouse 80 m high is 30°. Find the distance of the ship from the lighthouse.
Correct Answer: A. 80√3 m
Explanation: tan30°=80/d ⇒ d=80√3.
Explanation: tan30°=80/d ⇒ d=80√3.
7. A ladder 10 m long reaches the top of a wall making an angle of 60° with ground. Find height of wall.
Correct Answer: B. 5√3 m
Explanation: sin60°=height/10 ⇒ √3/2=h/10 ⇒ h=5√3.
Explanation: sin60°=height/10 ⇒ √3/2=h/10 ⇒ h=5√3.
8. The angle of elevation of a balloon is 60°. If it is 100 m above ground, find horizontal distance.
Correct Answer: D. 50√3 m
Explanation: tan60°=100/d ⇒ √3=100/d ⇒ d=100/√3=50√3.
Explanation: tan60°=100/d ⇒ √3=100/d ⇒ d=100/√3=50√3.
9. From top of a 20 m tower, angle of depression of a point is 45°. Distance is:
Correct Answer: B. 20 m
Explanation: tan45°=20/d ⇒ d=20 m.
Explanation: tan45°=20/d ⇒ d=20 m.
10. A pole 15 m high casts shadow 15√3 m. Angle?
Correct: A.30°
tanθ=15/(15√3)=1/√3 ⇒ θ=30°.
tanθ=15/(15√3)=1/√3 ⇒ θ=30°.
11. A tree 14 m tall seen at 45°. Distance?
Correct: A.14m
tan45°=14/d ⇒ d=14m.
tan45°=14/d ⇒ d=14m.
12. Height of tower if distance 10m & angle 60°?
Correct:B.10√3
tan60°=h/10 ⇒ h=10√3.
tan60°=h/10 ⇒ h=10√3.
13. Kite string 50m makes 30°. Height?
Correct:A.25m
sin30°=h/50 ⇒ h=25m.
sin30°=h/50 ⇒ h=25m.
14. Ladder 8m at 30°. Height?
Correct:A.4m
sin30°=h/8 ⇒ h=4m.
sin30°=h/8 ⇒ h=4m.
15. From 100m distance, angle 45°. Height?
Correct:B.100
tan45°=h/100 ⇒ h=100m.
tan45°=h/100 ⇒ h=100m.
16. 24m tower, angle 30°. Distance?
Correct:A.24√3
tan30°=24/d ⇒ d=24√3.
tan30°=24/d ⇒ d=24√3.
17. Height 10m, angle 60°. Distance?
Correct:C.10/√3
tan60°=10/d ⇒ d=10/√3.
tan60°=10/d ⇒ d=10/√3.
18. A balloon 50m high seen at 45°. Distance?
Correct:B.50
tan45°=50/d ⇒ d=50.
tan45°=50/d ⇒ d=50.
19. Height if distance 20m & angle 30°?
Correct:B.20/√3
tan30°=h/20 ⇒ h=20/√3.
tan30°=h/20 ⇒ h=20/√3.
20. From 30m tower, depression 60°. Distance?
Correct:A.10
tan60°=30/d ⇒ d=30/√3=10√3? Correction: tan60°=√3=30/d ⇒ d=30/√3=10√3.
tan60°=30/d ⇒ d=30/√3=10√3? Correction: tan60°=√3=30/d ⇒ d=30/√3=10√3.
