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CBSE Class 11 Chemistry MCQs: Electron Transfer and Oxidation State – NCERT Practice Test
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Introduction Paragraph
Understanding Electron Transfer and Oxidation State is one of the foundational aspects of Chapter 8: Redox Reactions in CBSE Class 11 Chemistry (Part B: Inorganic Chemistry). This topic focuses on how electrons are exchanged during chemical reactions, the rules for assigning oxidation numbers, and the identification of oxidizing and reducing agents. Mastering these concepts is crucial for performing accurate redox balancing, titration analysis, and solving higher-level problems in electrochemistry and thermodynamics.
This online MCQ practice test is prepared strictly as per the NCERT syllabus and follows the CBSE Class 11 Chemistry board exam pattern. It helps students strengthen their understanding of oxidation, reduction, and redox mechanisms through concept-based multiple-choice questions. Each question includes detailed answers and explanations to enhance learning and conceptual clarity.
These Electron Transfer and Oxidation State MCQs are ideal for self-assessment, board exam preparation, and entrance tests such as JEE Main and NEET, ensuring solid conceptual grounding in Inorganic Chemistry.
Sample MCQs (with Answers and Explanations)
Q1. Oxidation is defined as:
A) Gain of electrons B) Loss of electrons C) Gain of protons D) Loss of neutrons
Answer: B) Loss of electrons
Explanation: Oxidation involves the loss of electrons by an atom or ion, resulting in an increase in oxidation number.
Q2. The oxidation number of sulfur in SO₄²⁻ is:
A) +6 B) +4 C) -2 D) 0
Answer: A) +6
Explanation: Let oxidation number of sulfur = x. Then, x + 4(-2) = -2 ⇒ x = +6.
Q3. In H₂O₂, the oxidation state of oxygen is:
A) -2 B) -1 C) 0 D) +1
Answer: B) -1
Explanation: In peroxides like hydrogen peroxide (H₂O₂), each oxygen atom has an oxidation state of -1.
Q4. In the redox reaction: Zn + Cu²⁺ → Zn²⁺ + Cu, zinc acts as:
A) Oxidizing agent B) Reducing agent C) Catalyst D) Spectator ion
Answer: B) Reducing agent
Explanation: Zinc loses electrons (oxidized), thus reducing Cu²⁺ to Cu. Hence, Zn is the reducing agent.
Q5. The oxidation state of oxygen in OF₂ is:
A) -2 B) +2 C) -1 D) 0
Answer: B) +2
Explanation: Since fluorine is more electronegative (-1 each), the oxidation state of oxygen must be +2 to balance OF₂.
✅ Highlight:
These NCERT-based CBSE Class 11 Chemistry MCQs on Electron Transfer and Oxidation State are designed strictly according to the syllabus, making them perfect for board exam preparation and concept mastery.