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CBSE Class 11 Chemistry MCQs on Stoichiometry and Mole Concept – Free Online Test
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NCERT Class 11 Chemistry MCQs – Stoichiometry and Mole Concept Online Quiz
📚 Introduction
The topic “Stoichiometry and Mole Concept” is one of the most fundamental areas of Physical Chemistry in CBSE Class 11. It forms the basis for understanding chemical reactions, quantitative analysis, and the mole-based approach to problem-solving. This online MCQ practice test has been carefully designed as per the latest NCERT Class 11 Chemistry syllabus, making it ideal for CBSE board exam preparation and competitive exams like JEE and NEET.
Each question in this test covers essential subtopics such as the mole concept, empirical and molecular formulas, stoichiometric calculations, limiting reagents, and mass-volume relationships. By attempting these Stoichiometry and Mole Concept MCQs, students can strengthen their conceptual understanding, test their accuracy, and enhance their speed in solving numerical problems.
These practice questions are crafted to help learners self-assess their preparation level, understand common mistakes, and achieve excellence in the CBSE Class 11 Chemistry board examination.
🧩 6. Sample MCQs (with Answers & Explanations):
Q1. The number of atoms in 2 moles of oxygen gas (O₂) is:
A. 6.022×10²³ B. 1.204×10²⁴ C. 2.408×10²⁴ D. 3.011×10²³
✅ Answer: C. 2.408×10²⁴
💡 Explanation: 1 mole O₂ = 6.022×10²³ molecules; each molecule has 2 atoms → 2 × 6.022×10²³ × 2 mol = 2.408×10²⁴ atoms.
Q2. The molar mass of CaCO₃ is:
A. 84 g/mol B. 100 g/mol C. 120 g/mol D. 40 g/mol
✅ Answer: B. 100 g/mol
💡 Explanation: Ca (40.08) + C (12.01) + 3×O (48.00) = 100.09 g/mol.
Q3. 0.5 mole of NaCl contains how many formula units?
A. 1.505×10²³ B. 3.011×10²³ C. 6.022×10²³ D. 1.204×10²⁴
✅ Answer: B. 3.011×10²³
💡 Explanation: 0.5 mol × Avogadro’s number (6.022×10²³) = 3.011×10²³ units.
Q4. How many moles of water are produced from 4 moles of hydrogen gas reacting completely with oxygen?
A. 2 mol B. 3 mol C. 4 mol D. 6 mol
✅ Answer: C. 4 mol
💡 Explanation: 2H₂ + O₂ → 2H₂O; 4 mol H₂ → 4 mol H₂O (1:1 ratio).
Q5. The empirical formula of a compound with 40% carbon, 6.7% hydrogen, and 53.3% oxygen is:
A. CH₂O B. C₂H₄O₂ C. CHO D. C₃H₆O₃
✅ Answer: A. CH₂O
💡 Explanation: Simplest whole-number ratio of C:H:O = 1:2:1 → CH₂O (formaldehyde).